Many times in geometry, if we take three special lines through the vertices of a triangle, or cevians, then their reflections about the corresponding angle bisectors, called isogonal lines, will also have interesting properties. For instance, if three cevians of a triangle intersect at a point P, then their isogonal lines also intersect at a point, called the isogonal conjugate of P. The symmedians illustrate this fact.
In the diagram, the medians intersect at the centroid G.
Because the symmedians are isogonal to the medians, the symmedians also intersect at a single point, L.
This point is called the triangle's symmedian point, or alternatively the Lemoine point or Grebe point. The dotted lines are the angle bisectors; the symmedians and medians are symmetric about the angle bisectors
Construction of the symmedian
Let ABC be a triangle. Construct a point D by intersecting the tangents from B and C to the circumcircle. Then AD is the symmedian of the triangle ABC. first proof. Let the reflection of AD across the angle bisector of ∠BAC meet BC at M'. Then: second proof. Define D' as the isogonal conjugate of D. It is easy to see that the reflection of CD about the bisector is the line through C parallel to AB. The same is true for BD, and so, ABD'C is a parallelogram. AD' is clearly the median, because a parallelogram's diagonals bisect each other, and AD is its reflection about the bisector. third proof. Let ω be the circle with center D passing through B and C, and let O be the Circumcenter of ABC, Say lines AB and AC intersect ω at P and Q, respectively. Since ∠ABC = ∠AQP, triangles ABC and AQP are similar. Since ∠PBQ = ∠BQC+∠BAC = 1/2 = 90◦, we see that PQ is a diameter of ω and hence passes through D. Let M be the midpoint of BC. Since D is the midpoint of QP, the similarity implies that ∠BAM=∠QAD, from which the result follows. fourth proof. Let S be the midpoint of the arc BC. BS=SC, so AS is the angle bisector of ∠BAC. Let M be the midpoint of BC, and It follows that D is the Inverse of M with respect to the circumcircle. From that, we know that the circumcircle is an Apollonian circle with foci M and D. So AS is the bisector of angle ∠DAM, and we have achieved our wanted result.
Tetrahedra
The concept of a symmedian point extends to tetrahedra. Given a tetrahedron ABCD two planes P and Q through AB are isogonal conjugates if they form equal angles with the planes ABC and ABD. Let M be the midpoint of the side CD. The plane containing the side AB that is isogonal to the plane ABM is called a symmedian plane of the tetrahedron. The symmedian planes can be shown to intersect at a point, the symmedian point. This is also the point that minimizes the squared distance from the faces of the tetrahedron.
