After reading the expression, pop the operators off the stack and add them to the output.
:In this case there is only one, "+".
Output:
This already shows a couple of rules:
All numbers are pushed to the output when they are read.
At the end of reading the expression, pop all operators off the stack and onto the output.
Graphical illustration
Graphical illustration of algorithm, using a three-way railroad junction. The input is processed one symbol at a time: if a variable or number is found, it is copied directly to the output a), c), e), h). If the symbol is an operator, it is pushed onto the operator stack b), d), f). If the operator's precedence is greater than that of the operators at the top of the stack or the precedents are equal and the operator is left associative, then that operator is popped off the stack and added to the output g). Finally, any remaining operators are popped off the stack and added to the output i).
The algorithm in detail
Important terms: Token, Function, Operator associativity, Precedence while there are tokens to be read: read a token. if the token is a number, then: push it to the output queue. else if the token is a function then: push it onto the operator stack else if the token is an operator then: while and or ) and ): pop operators from the operator stack onto the output queue. push it onto the operator stack. else if the token is a left parenthesis, then: push it onto the operator stack. else if the token is a right parenthesis, then: while the operator at the top of the operator stack is not a left parenthesis: pop the operator from the operator stack onto the output queue.
if there is a left parenthesis at the top of the operator stack, then: pop the operator from the operator stack and discard it if there are no more tokens to read then: while there are still operator tokens on the stack:
pop the operator from the operator stack onto the output queue. exit. To analyze the runningtime complexity of this algorithm, one has only to note that each token will be read once, each number, function, or operator will be printed once, and each function, operator, or parenthesis will be pushed onto the stack and popped off the stack once—therefore, there are at most a constant number of operations executed per token, and the running time is thus O—linear in the size of the input. The shunting yard algorithm can also be applied to produce prefix notation. To do this one would simply start from the end of a string of tokens to be parsed and work backwards, reverse the output queue, and flip the left and right parenthesis behavior. And changing the associativity condition to right.
Detailed example
Input: The symbol ^ represents the power operator. Input: