Quadratic Jordan algebra


In mathematics, quadratic Jordan algebras are a generalization of Jordan algebras introduced by. The fundamental identities of the quadratic representation of a linear Jordan algebra are used as axioms to define a quadratic Jordan algebra over a field of arbitrary characteristic. There is a uniform description of finite-dimensional simple quadratic Jordan algebras, independent of characteristic. If 2 is invertible in the field of coefficients, the theory of quadratic Jordan algebras reduces to that of linear Jordan algebras.

Definition

A quadratic Jordan algebra consists of a vector space A over a field K with a distinguished element 1 and a quadratic map of A into the K-endomorphisms of A, a ↦ Q, satisfying the conditions:
Further, these properties are required to hold under any extension of scalars.

Elements

An element a is invertible if Q is invertible and there exists b such that Q is the inverse of Q and Q'b = a: such b is unique and we say that b is the inverse of a. A Jordan division algebra''' is one in which every non-zero element is invertible.

Structure

Let B be a subspace of A. Define B to be a quadratic ideal or an inner ideal if the image of Q is contained in B for all b in B; define B to be an outer ideal if B is mapped into itself by every Q for all a in A. An ideal of A is a subspace which is both an inner and an outer ideal. A quadratic Jordan algebra is simple if it contains no non-trivial ideals.
For given b, the image of Q is an inner ideal: we call this the principal inner ideal on b.
The centroid Γ of A is the subset of EndK consisting of endomorphisms T which "commute" with Q in the sense that for all a
The centroid of a simple algebra is a field: A is central if its centroid is just K.

Examples

Quadratic Jordan algebra from an associative algebra

If A is a unital associative algebra over K with multiplication × then a quadratic map Q can be defined from A to EndK by Q : b ↦ a × b × a. This defines a quadratic Jordan algebra structure on A. A quadratic Jordan algebra is special if it is isomorphic to a subalgebra of such an algebra, otherwise exceptional.

Quadratic Jordan algebra from a quadratic form

Let A be a vector space over K with a quadratic form q and associated symmetric bilinear form q = q - q - q. Let e be a "basepoint" of A, that is, an element with q = 1. Define a linear functional T = q and a "reflection" y∗ = Te - y. For each x we define Q by
Then Q defines a quadratic Jordan algebra on A.

Quadratic Jordan algebra from a linear Jordan algebra

Let A be a unital Jordan algebra over a field K of characteristic not equal to 2. For a in A, let L denote the left multiplication map in the associative enveloping algebra
and define a K-endomorphism of A, called the quadratic representation, by
Then Q defines a quadratic Jordan algebra.

Quadratic Jordan algebra defined by a linear Jordan algebra

The quadratic identities can be proved in a finite-dimensional Jordan algebra over R or C following Max Koecher, who used an invertible element. They are also easy to prove in a Jordan algebra defined by a unital associative algebra since in that case Qb = aba. They are valid in any Jordan algebra over a field of characteristic not equal to 2. This was conjectured by Jacobson and proved in : Macdonald showed that if a polynomial identity in three variables, linear in the third, is valid in any special Jordan algebra, then it holds in all Jordan algebras. In an elementary proof, due to McCrimmon and Meyberg, is given for Jordan algebras over a field of characteristic not equal to 2.

Koecher's proof

Koecher's arguments apply for finite-dimensional Jordan algebras over the real or complex numbers.

Fundamental identity I

An element a in A is called invertible if it is invertible in R or C. If b denotes the inverse, then power associativity of a shows that L and L commute.
In fact a is invertible if and only if Q is invertible. In that case
Indeed if Q is invertible it carries R onto itself. On the other hand Q1 = a2, so
The Jordan identity
can be polarized by replacing a by a + tc and taking the coefficient of t. Rewriting this as an operator applied to c yields
Taking b = a−1 in this polarized Jordan identity yields
Replacing a by its inverse, the relation follows if L and L are invertible. If not it holds for a + ε1 with ε arbitrarily small and hence also in the limit.
For c in A and F a function on A with values in End A, let
DcF be the derivative at t = 0 of F. Then
where Q if the polarization of Q
Since L commutes with L
Hence
so that
Applying Dc to L'Q = L and acting on b = c−1 yields
On the other hand L is invertible on an open dense set where Q'b must also be invertible with
Taking the derivative Dc in the variable b in the expression above gives
This yields the fundamental identity for a dense set of invertible elements, so it follows in general by continuity. The fundamental identity implies that c = Qb is invertible if a and b are invertible and gives a formula for the inverse of Q. Applying it to c gives the inverse identity in full generality.

Commutation identity I

As shown above, if a is invertible,
Taking Dc with a as the variable gives
Replacing a by a−1 gives, applying Q and using the fundamental identity gives
Hence
Interchanging b and c gives
On the other hand is defined by, so this implies
so that for a invertible and hence by continuity for all a

Mccrimmon–Meyberg proof

Commutation identity II

The Jordan identity can be polarized by replacing a by a + tc and taking the coefficient of t. This gives
In operator notation this implies
Polarizing in a again gives
Written as operators acting on d, this gives
Replacing c by b and b by a gives
Also, since the right hand side is symmetric in b and c, interchanging b and c on the left and subtracting, it follows that the commutators are derivations of the Jordan algebra.
Let
Then Q commutes with L by the Jordan identity.
From the definitions if is the associated symmetric bilinear mapping, then and
Moreover
Indeed
By the second and first polarized Jordan identities this implies
The polarized version of is
Now with, it follows that
So by the last identity with ab in place of b this implies the commutation identity:
The identity Q'R = RQ can be strengthened to
Indeed applied to c, the first two terms give
Switching b and c'' then gives

Fundamental identity II

The identity is proved using the Lie bracket relations
Indeed the polarization in c of the identity gives
Applying both sides to d, this shows that
In particular these equations hold for x = ab. On the other hand if T = then D = Tz is a derivation of the Jordan algebra, so that
The Lie bracket relations follow because R = T + L.
Since the Lie bracket on the left hand side is antisymmetric,
As a consequence
Indeed set a = y, b = x, c = z, d = x and make both sides act on y.
On the other hand
Indeed this follows by setting x = Qb in
Hence, combining these equations with the strengthened commutation identity,

Linear Jordan algebra defined by a quadratic Jordan algebra

Let A be a quadratic Jordan algebra over R or C. Following, a linear Jordan algebra structure can be associated with A such that, if L is Jordan multiplication, then the quadratic structure is given by Q = 2L2 − L.
Firstly the axiom Q'R = R
Q can be strengthened to
Indeed applied to c, the first two terms give
Switching b and c then gives
Now let
Replacing b by a and a by 1 in the identity above gives
In particular
If furthermore a is invertible then
Similarly if b is invertible
The Jordan product is given by
so that
The formula above shows that 1 is an identity. Defining a2 by a∘a = Q1, the only remaining condition to be verified is the Jordan identity
In the fundamental identity
Replace a by a + t, set b = 1 and compare the coefficients of t2 on both sides:
Setting b = 1 in the second axiom gives
and therefore L must commute with L''.

Shift identity

In a unital linear Jordan algebra the shift identity asserts that
Following, it can be established as a direct consequence of polarized forms of the fundamental identity and the commutation or homotopy identity. It is also a consequence of Macdonald's theorem since it is an operator identity involving only two variables.
For a in a unital linear Jordan algebra A the quadratic representation is given by
so the corresponding symmetric bilinear mapping is
The other operators are given by the formula
so that
The commutation or homotopy identity
can be polarized in a. Replacing a by a + t1 and taking the coefficient of t gives
The fundamental identity
can be polarized in a. Replacing a by a +t1 and taking the coefficients of t gives
Combining the two previous displayed identities yields
Replacing a by a +t1 in the fundamental identity and taking the coefficient of t2 gives
Since the right hand side is symmetric this implies
These identities can be used to prove the shift identity:
It is equivalent to the identity
By the previous displayed identity this is equivalent to
On the other hand the bracketed terms can be simplified by the third displayed identity. It implies that both sides are equal to.
For finite-dimensional unital Jordan algebras, the shift identity can be seen more directly using mutations. Let a and b be invertible, and let
be the Jordan multiplication in Ab. Then
. Moreover
on the other hand and similarly with a and b interchanged. Hence
Thus
so the shift identity follows by cancelling Q. A density argument allows the invertibility assumption to be dropped.

Jordan pairs

A linear unital Jordan algebra gives rise to a quadratic mapping Q and associated mapping R satisfying the fundamental identity, the commutation of homotopy identity and the shift identity. A Jordan pair consists of two vector space and two quadratic mappings from to. These determine bilinear mappings from to by the formula where. Omitting ± subscripts, these must satisfy
the fundamental identity
the commutation or homotopy identity
and the shift identity
A unital Jordan algebra A defines a Jordan pair by taking V± = A with its quadratic structure maps Q and R.